Math Scripts: Algebra I

By Carol Armstrong Hardee

Math Scripts: Algebra 1 is a supplemental resource to any Algebra 1 course. It is designed to allow students to practice solving equations and inequalities studied in Algebra 1 using a script. The script provides word-for-word steps using the rules of equations, inequalities, and order of operations. Students can partner with other students and speak the parts in the script that describes step by step how to solve what is given. They have a great opportunity to write what they are saying, which helps them to process how what they are saying is related to how to denote the solution process symbolically. In other words, they are not only able to say the correct process, but they see how it should be written, building their literacy. There are different levels for each topic, so students can begin at an entry level and continue with more complex scripts. Speaking the language of math by performing math scripts will help your student become more fluent in math.

• Language: English
• Publisher: Christian Faith Publishing, Inc.
• Release date: Jan 12, 2022
• ISBN: 9781098039677

Book preview

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Math Scripts

Algebra I

Carol Armstrong Hardee

ISBN 978-1-0980-3968-4 (paperback)

ISBN 978-1-0980-3967-7 (digital)

Copyright © 2020 by Carol Armstrong Hardee

All rights reserved. No part of this publication may be reproduced, distributed, or transmitted in any form or by any means, including photocopying, recording, or other electronic or mechanical methods without the prior written permission of the publisher. For permission requests, solicit the publisher via the address below.

Christian Faith Publishing, Inc.

832 Park Avenue

Meadville, PA 16335

www.christianfaithpublishing.com

Printed in the United States of America

Table of Contents

Topic 1: Order of Operations

Topic 1: Order of Operations

Topic 1: Order of Operations

Topic 1: Order of Operations

Topic 2: Solving Linear Equations and Inequalities

Topic 2: Solving Linear Equations and Inequalities

Topic 2: Solving Linear Equations and Inequalities

Topic 2: Solving Linear Equations and Inequalities

Topic 2: Solving Linear Equations and Inequalities

Topic 2: Solving Linear Equations and Inequalities

Topic 2: Solving Linear Equations and Inequalities

Topic 2: Solving Linear Equations and Inequalities

Topic 3: Slope Formula

Topic 3: Slope Formula

Topic 3: Slope Formula

Topic 3: Slope Formula

Topic 3: Slope Formula

Topic 4: Writing Linear Equations Using the Slope-Intercept Formula

Topic 4: Writing Linear Equations Using the Slope-Intercept Formula

Topic 4: Writing Linear Equations Using the Slope-Intercept Formula

Topic 4: Writing Linear Equations Using the Slope-Intercept Formula

Topic 4: Writing Linear Equations Using the Slope-Intercept Formula

Topic 5: Writing Linear Equations Using the Point-Slope Formula

Topic 5: Writing Linear Equations using the Point-Slope Formula

Topic 5: Writing Linear Equations using the Point-Slope Formula

Topic 5: Writing Linear Equations using the Point-Slope Formula

Topic 6: Writing Linear Equations in Standard Form

Topic 6: Writing Linear Equations in Standard Form

Topic 6: Writing Linear Equations in Standard Form

Topic 6: Writing Linear Equations in Standard Form

Topic 7: Writing Equations of Parallel Lines

Topic 7: Writing Equations of Parallel Lines

Topic 7: Writing Equations of Parallel Lines

Topic 7: Writing Equations of Parallel Lines

Topic 8: Writing Equations of Perpendicular Lines

Topic 8: Writing Equations of Perpendicular Lines

Topic 8: Writing Equations of Perpendicular Lines

Topic 8: Writing Equations of Perpendicular Lines

Topic 9: Properties of Exponents

Topic 9: Properties of Exponents

Topic 9: Properties of Exponents

Topic 9: Properties of Exponents

Topic 10: Radicals and Rational Exponents

Topic 10: Radicals and Rational Exponents

Topic 10: Radicals and Rational Exponents

Topic 10: Radicals and Rational Exponents

Topic 11: Solving a Two-by-Two System of Linear Equations Using the Substitution Method

Topic 11: Solving a Two-by-Two System of Linear Equations Using the Substitution Method

Topic 11: Solving a Two-by-Two System of Linear Equations Using the Substitution Method

Topic 11: Solving a Two-by-Two System of Linear Equations Using the Substitution Method

Topic 12: Solving a Two-by-Two System of Linear Equations Using the Elimination Method

Topic 12: Solving a Two-by-Two System of Linear Equations Using the Elimination Method

Topic 12: Solving a Two-by-Two System of Linear Equations Using the Elimination Method

Topic 12: Solving a Two-by-Two System of Linear Equations Using the Elimination Method

Topic 13: Adding and Subtracting Polynomial Expressions

Topic 13: Adding and Subtracting Polynomial Expressions

Topic 13: Adding and Subtracting Polynomial Expressions

Topic 13: Adding and Subtracting Polynomial Expressions

Topic 14: Multiplying Polynomials

Topic 14: Multiplying Polynomials

Topic 14: Multiplying Polynomials

Topic 14: Multiplying Polynomials

Topic 14: Multiplying Polynomials

Topic 14: Multiplying Polynomials

Topic 14: Multiplying Polynomials

Topic 15: Factoring Trinomials

Topic 15: Factoring Polynomials

Topic 15: Factoring Polynomials

Topic 15: Factoring Polynomials

Topic 16: Writing and Solving Direct Variation Equations

Topic 16: Writing and Solving Direct Variation Equations

Topic 16: Writing and Solving Direct Variation Equations

Topic 16: Writing and Solving Direct Variation Equations

Topic 17: Solving Quadratic Equations using the Quadratic Formula

Topic 17: Solving Quadratic Equations using the Quadratic Formula

Topic 17: Solving Quadratic Equations using the Quadratic Formula

Topic 17: Solving Quadratic Equations Using the Quadratic Formula

Topic 18: Solving Quadratic Equations by Factoring

Topic 18: Solving Quadratic Equations by Factoring

Topic 18: Solving Quadratic Equations by Factoring

Topic 18: Solving Quadratic Equations by Factoring

Topic 19: Solving Quadratic Equations by Completing the Square

Topic 19: Solving Quadratic Equations by Completing the Square

Topic 19: Solving Quadratic Equations by Completing the Square

Topic 19: Solving Quadratic Equations by Completing the Square

Topic 1

Order

of

Operations

Order of Operations

Topic 1:

Order of Operations

Script 1

Order of Operations with Fazi and Monroe

Simplify

FAZI

Okay. We have to simplify two times the difference, five squared minus fifteen plus nine divided by three.

MONROE

The order of operations says to simplify parentheses first, then exponents, then multiplication and division from left to right, then addition and subtraction from left to right.

FAZI

That means first, we find the value of five squared.

MONROE

Why not do nine divided by three?

FAZI

Because you do parentheses before division—PEMDAS, okay?

MONROE

Oh yeah. That’s right.

FAZI

So anyway, that makes two, parenthesis, twenty-five minus fifteen, plus nine over three.

MONROE

Okay. Then?

FAZI

Then twenty-five minus fifteen is ten. So we have two times ten plus nine over three.

MONROE

So now we multiply two by ten, so that’s twenty plus nine over three.

FAZI

And nine over three is three, so we now have twenty plus three.

MONROE

So that’s twenty-three.

Topic 1:

Order of Operations

Script 2

Order of Operations with Spencer and Maya

Simplify

SPENCER

We need to simplify nine times the difference, fourteen-halves minus five plus four squared.

MAYA

The order of operations says to simplify parentheses first, then exponents, then multiplication and division from left to right, then addition and subtraction from left to right.

SPENCER

So we start with parentheses.

MAYA

In the parentheses we have fourteen over two minus five.

SPENCER

Right. So we do the fourteen over two because that’s division, and we do division before subtraction.

MAYA

Oh yeah. That’s right.

SPENCER

Fourteen divided by two is seven.

MAYA

And seven minus five is two.

SPENCER

So now we have nine times two plus four squared.

MAYA

Weren’t we supposed to do the exponents before the division?

SPENCER

Hey, that’s right. But the division was inside the parentheses, and we’re supposed to do parentheses before exponents.

MAYA

Okay. Then since four squared is sixteen, we get nine times two plus sixteen.

SPENCER

Nine times two is eighteen plus sixteen is thirty-four.

MAYA

The answer is thirty-four.

Topic 1:

Order of Operations

Script 3

Order of Operations with Anahi and David

Simplify

DAVID

Seven plus six times the quotient, three squared minus four divided by five.

ANAHI

The order of operations says to simplify parentheses first, then exponents, then multiplication and division from left to right, then addition and subtraction from left to right.

DAVID

In parentheses we have three squared minus four, all divided by five. So what do we do first?

ANAHI

Well, we do parentheses first; and inside the parentheses we do exponents, subtraction, and then division.

DAVID

But don’t we do division before subtraction?

ANAHI

But the subtraction is part of the numerator, so we have to do that together. That’s like having parentheses around the numerator.

DAVID

That’s right. Okay, three squared is nine and nine minus four is five.

ANAHI

And five over five is one.

DAVID

So we have seven plus six times one.

ANAHI

Six times one is six.

DAVID

Now we add seven plus six. That’s thirteen.

ANAHI

So the answer is thirteen.

Topic 1:

Order of Operations

Script 4

Order of Operations with Raymond and Marco

Simplify

RAYMOND

Okay, we have to simplify six squared minus the quotient, nine times the sum, twelve-thirds plus eight, all divided by three.

MARCO

The order of operations says to simplify parentheses first, then exponents, then multiplication and division from left to right, then addition and subtraction from left to right.

RAYMOND

In parentheses we have twelve-thirds plus eight. So what do we do first?

MARCO

Well, we do twelve-thirds because that’s four, then we just add eight.

RAYMOND

Well, four plus eight is twelve.

MARCO

Okay. Then that makes six squared minus nine times twelve over three. What’s nine times twelve?

RAYMOND

Let’s see. Nine times twelve is one hundred eight.

MARCO

And one-o-eight divided by three is thirty-six.

RAYMOND

Wow.

MARCO

Wow, what?

RAYMOND

Well, six squared is thirty-six, so…

MARCO

(finishing Raymond’s thought)

So thirty-six minus thirty-six is zero. Wow.

Topic 2

Solving

Linear Equations

and Inequalities

Solving Linear Equations and Inequalities

Topic 2:

Solving Linear Equations and Inequalities

Script 1

Solving Equations with Karla and Shelby

Find the value of if 15 . Justify each step.

KARLA

Okay, we have to solve for x in the equation fifteen plus two equals thirty-nine.

SHELBY

We should start by subtracting fifteen from both sides of the equation to isolate the x term.

KARLA

Why?

SHELBY

The subtraction property.

KARLA

So that means that we need to find thirty-nine minus fifteen.

SHELBY

Which is twenty-four.

KARLA

So now we have two equals twenty-four.