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Complex Variables for Scientists and Engineers: Second Edition
Complex Variables for Scientists and Engineers: Second Edition
Complex Variables for Scientists and Engineers: Second Edition
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Complex Variables for Scientists and Engineers: Second Edition

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This outstanding text for undergraduate students of science and engineering requires only a standard course in elementary calculus. Designed to provide a thorough understanding of fundamental concepts and create the basis for higher-level courses, the treatment features numerous examples and extensive exercise sections of varying difficulty, plus answers to selected exercises.
The two-part approach begins with the development of the primary concept of analytic function, advancing to the Cauchy integral theory, the series development of analytic functions through evaluation of integrals by residues, and some elementary applications of harmonic functions. The second part introduces some of the deeper aspects of complex function theory: mapping properties of analytic functions, applications to various vector field problems with boundary conditions, and a collection of further theoretical results. 1990 edition.
LanguageEnglish
Release dateFeb 19, 2014
ISBN9780486782225
Complex Variables for Scientists and Engineers: Second Edition

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    Complex Variables for Scientists and Engineers - John D. Paliouras

    EDITION

    I  Foundations of Complex Variables

    CHAPTER 1

    Complex Numbers

    SECTION 1 COMPLEX NUMBERS AND THEIR ALGEBRA

    It is assumed that the reader is familiar with the system of real numbers and their elementary algebraic properties. Our work in this book will take us to a larger system of numbers that have been given the unfortunate name imaginary or complex numbers. A historical account of the discovery of such numbers and of their development into prominence in the world of mathematics is outside the scope of this book. Suffice it to say that the need for such numbers arose from the need to find square roots of negative numbers.

    The system of complex numbers can be formally introduced by use of the concept of an ordered pair (a, b) of real numbers. The set of all such pairs with appropriate operations defined on them can be defined to constitute the system of complex numbers. The reader who is interested in this formal approach is referred to Appendix 1(A). Here, with due apologies to the formalists, we shall proceed to define the complex numbers in the more conventional, if somewhat incomplete manner. We will see that the system of complex numbers is a natural extension of the real numbers in the sense that a real number is a special case of a complex number.

    The set of complex numbers is defined to be the totality of all quantities of the form

    where a and b are real numbers and i² = − 1. To the reader who may wonder what is so incomplete about this approach of defining the complex numbers, we point out that nothing is said as to the meaning of the implied multiplication in the terms ib and bi.

    If z = a + ib is any complex number, a is called the real part or real component of z and b is called the imaginary part or imaginary component of z; we sometimes denote them

    respectively, and reemphasize the fact that both Re (z) and Im (z) are real numbers. If Re (z) = 0 and Im (z) ≠ 0, then z is called pure imaginary; for example, z = 3i is such a number. In particular, if Re (z) = 0 and Im (z) = 1, we write z = i and we call this number the imaginary unit. If Im (z) = 0, z reduces to the real number Re (z); in that sense, one can think of any real number x as being a complex number of the form z = x + 0i. This illustrates the fact that was noted earlier, namely, that the system of complex numbers is an extension of the system of real numbers; equivalently, we say that the latter is a special case of the former.

    We now proceed to define some of the basic operations on complex numbers. For the remainder of this section,

    are three arbitrary complex numbers.

    Equality of complex numbers is defined quite naturally. Thus two complex numbers are equal provided that their real parts and their imaginary parts are, respectively, equal; that is,

    The sum of two complex numbers is obtained by adding the real parts and the imaginary parts, respectively; that is,

    The product of z1 and z2 is found by multiplying the two numbers as if they were two binomials, using the reduction formula i² = − 1 and collecting like terms; thus

    Then, using the preceding formula, one defines the nonnegative integral powers of a complex number z as in the case of real numbers. Thus

    The zero (additive identity) of the system of complex numbers is the number

    which we simply write 0, and the unity (multiplicative identity) is the number

    which we write simply as 1. Using the definitions of addition and multiplication given above, we find that it is very easy to show that for any complex number z = x + iy,

    thus verifying that these two numbers are, indeed, the additive and multiplicative identities of the system. If z ≠ 0, the zero power of z is 1:

    Again, if z is any complex number, there is one and only one complex number, which we will denote by − z, such that

    z is called the negative of z and it is easy to verify that

    For any nonzero complex number z = x + iy there is one and only one complex number, which we will denote by z−1, such that

    z−1 is called the reciprocal (multiplicative inverse) of z and a direct calculation from the preceding equation yields

    See the Note prior to Example 1.

    To facilitate further algebraic manipulations, we now define the difference of two numbers by

    which, through an easy calculation, yields

    Finally, we define the quotient of two numbers by

    In particular, 1 / z = z−1. A straightforward, if somewhat involved, calculation in which we utilize the formula for the reciprocal, above, yields the formula

    See the Note prior to Example 1.

    In addition to the operations defined above, we have a new operation, called conjugation, defined on complex numbers as follows: If z = x + iy, then the conjugate of z, is defined by

    Unlike the four binary operations defined earlier, conjugation is a unary operation; that is, it acts on one number at a time and has the effect of negating the imaginary part of the number.

    ALGEBRAIC PROPERTIES OF COMPLEX NUMBERS

    The operations defined above obey the following laws.

    1.Commutative laws:

    2.Associative laws:

    3.Distributive law of multiplication over addition:

    4.Distributive laws of conjugation:

    = [Re (z)]² + [Im (z)]².

    Some of these properties are proved in the examples that follow; the remaining ones are left for the exercises.

    NOTE: With the concept of the conjugate at our disposal, calculation of the reciprocal of a complex number and of the quotient of two numbers becomes much easier than by use of the method suggested earlier. The reason for this revolves around the fact that the product of a complex number and its conjugate, which appears in the denominator of the following formulas, is a real number that makes the calculation of the quotient easier to effect. Specifically, we have the following two formulas :

    In other words, in order to find the quotient of two complex numbers, we multiply the numerator and the denominator by the conjugate of the denominator. As an exercise, the reader should verify that the results obtained by use of these two formulas agree with those obtained earlier.

    EXAMPLE 1

    If z = 5 − 5i and w = − 3 + 4i, find z + w, z w, z w, and z/w.

    Using the definitions of the respective operations, we find that

    EXAMPLE 2

    Prove the commutative law for addition: z1 + z2 = z2 + z1.

    We carry out this proof by using the corresponding law for real numbers, which states that for any two real numbers a and b, a + b = b + a. Thus we have

    EXAMPLE 3

    .

    Let z = a + bi and w = c + di. On the one hand, we have

    On the other hand,

    Clearly, the two sides are equal and the proof is complete.

    EXAMPLE 4

    Prove property 6: If z = x + iy, then z = x² + y².

    This property says that given any complex number, the product of the number and its conjugate is always a nonnegative real number, since it is the sum of squares of two real numbers.

    By now it should be apparent to the reader that most of the familiar algebraic properties of the real numbers are shared by the complex numbers. There is, however, a particular property of the real numbers, namely, the property of order, which does not carry over to the complex case. By this we mean that

    given two arbitrary complex numbers z and w such that z w, no reasonable meaning can be attached to the expression

    discussion and proof of this fact are left as an exercise for the reader. See Review Exercise 19 at the end of the chapter.

    EXERCISE 1

    A

    In Exercises 1.1 – 1.10, perform the operations indicated, reducing the answer to the form A + Bi.

    1.1(5 − 2i)+ (2+ 3i).

    1.2(2 − i) − (6 − 3i).

    1.3(2 + 3i)(−2 − 3i)

    1.4i(5 + i).

    1.5i · ī.

    1.6(a + bi)(a bi).

    1.76i/(6 − 5i).

    1.8(a + bi)/(a bi).

    1.91/(3 + 2i).

    1.10i², i³, i⁴, i⁵, …, i¹⁰.

    1.11From the results of Exercise 1.10, formulate a rule for all the positive integral powers of i and then for the negative ones.

    1.12Show that if z = − 1 − i, then z² + 2z + 2 = 0.

    1.13Show that the imaginary unit has the property that − i = i−l = ī.

    1.14If z = a + bi, express z² and z³ in the form A + Bi.

    1.15Reduce each of the following to the form A + Bi.

    (a)

    (b)

    (c)

    (d)i¹²³ − 4i⁹ − 4i.

    B

    1.16For which complex numbers, if any, is each of the following equations true?

    (a)z = −z.

    (b)z .

    (c)z = z−¹.

    (d)z .

    (e)z .

    (f) = z−1.

    1.17Prove that for any number z,

    1.18Prove that conjugation distributes over sums, differences, and quotients (see algebraic property 4 and Example 3).

    1.19Prove: z if and only if z is a real number.¹

    1.20Prove the commutative, associative, and distributive laws for complex numbers.

    1.21Prove that if z)², then z is either real or pure imaginary.

    1.22.

    1.23Prove: For any numbers z and w, z w = 2Re (z ).

    C

    1.24Prove: If zw = 0, then either z = 0 or w = 0, and conversely.

    1.25Prove that the zero of the complex number system is unique.

    1.26Prove that the unity of the complex number system is unique.

    1.27Prove that the negative of any complex number z is unique.

    1.28If z = x + iy is a nonzero complex number, derive z−l in terms of x and y and show that it is unique.

    SECTION 2 GEOMETRY OF COMPLEX NUMBERS

    The reader is familiar with certain correspondences between algebraic and geometric concepts that are described in analytic geometry. For example :

    1.The real numbers correspond to the points on a number line.

    2.| a b | corresponds to the distance between the numbers a and b.

    3.Equations in two variables correspond to curves in the plane.

    Similar correspondences exist and have very important uses in the theory and applications of complex variables. The basis for this entire concept is found in the very definition of a complex number, which creates, in a natural way, a one-to-one correspondence between the set of complex numbers and the points in the xy-plane. Thus using the usual Cartesian (rectangular) coordinates in the plane, we make the following association :

    The importance of this correspondence cannot be overemphasized, and it will become increasingly obvious in the subsequent developments. Indeed, the conceptual identification of complex numbers and points in the plane is so strong that the number a + ib and the point (a, b) become practically indistinguishable to the extent that we often talk about the number (a, b) or the point a + ib. In view of this identification, the familiar xy-plane will henceforth be referred to as the complex plane or z-plane, while the x-axis and the y-axis will be called real axis and imaginary axis, respectively.

    Going one step further, we can also identify a complex number with a two-dimensional vector. Thus

    the complex number a + ib can be thought of as a vector in the plane, emanating from the origin and terminating at the point (a, b).

    [See Appendix 1(A).]

    Now, given any number z = a + ib, the modulus (also called the length or the magnitude or the absolute value) of z, denoted | z |, is defined to be the length of the vector associated with z; that is,

    The argument (also referred to as the angle) of a complex number z ≠ 0, denoted arg z, is defined to be any one of the angles that the vector corresponding to z makes with the positive direction of the real axis; that is, for any nonzero z = a + ib,

    arg z is any angle θ (always expressed in radians) such that

    (See Fig. 1.1 and Remark 3.)

    Concerning the two concepts just defined, the following remarks are of importance.

    REMARK 1

    It is clear from the definition that the modulus of z represents the undirected distance of z from the origin and, therefore, it is a nonnegative real number. In particular, if z = a + ib is real (b = 0), then

    which is a definition of the absolute value of a real number a. This shows that the modulus of a complex number can be thought of as an extension of

    Figure 1.1 Modulus of z and arg z

    the concept of the absolute value of a real number. Equivalently, one can say that the absolute value of a real number is a special case of the modulus of a complex number.

    REMARK 2

    The notion of | z | representing the linear distance between 0 and z can be extended, quite naturally, to define the distance between the points z = a + ib and w = c + id to be the quantity

    That this is indeed the distance between the points (a, b) and (c, d) is easily shown as follows:

    the last expression being precisely the distance between the two points, as we know from analytic geometry.

    REMARK 3

    The argument of zero cannot be defined in a meaningful way. Algebraically, this is obvious since one would have to contend with the indeterminate form 0/0; geometrically, it is also obvious since the zero vector to which the number z = 0 corresponds has no length and hence cannot form any angle with the positive real axis.

    REMARK 4

    It is clear from the definition that the argument of a number is not a unique quantity; in fact, every nonzero z has an infinite number of distinct arguments, any two of which differ by a multiple of 2π. The situation here is identical with that encountered in analytic geometry when one expresses the coordinates of a point in polar form. For instance, consider the number z = 1 + i whose argument can be taken to be π/4 or 9π/4 or − 7π/4 or − 15π/4 or, in general, (π/4) + 2kπ, where k is any integer. This is a problem that in some instances we would like to avoid, and to do so, we introduce the concept of the principal value of arg z.

    For any number z ≠ 0, the principal value of arg z, denoted Arg z, is defined to be the unique value of arg z that satisfies the relation

    In view of Remark 4, it is easy to see that

    Figure 1.2 Example 1

    EXAMPLE 1

    has been plotted in Fig. 1.2. Its modulus is

    On the other hand, denoting arg z by θ, we find that

    Hence

    and

    EXAMPLE 2

    Find the number z for which | z | = 2 and arg z = π/4.

    Write z = x + iy. Since its argument, call it θ, is π/4, we have

    Hence

    and, since | z | = 2, it follows that x and y

    PROPERTIES OF | z |

    For any complex numbers z and w, the following properties are true.

    1.| z | = | −z |.

    2.| z w | = | w z |.

    3.| z |² = | z² | = z

    4.| zw | = | z | · | w |.

    provided that w ≠ 0.

    6.| | z | + | w | | ≤ | z | + | w |, triangle inequality.

    7.| | z |−| w | | ≤ | z w |.

    8.| z |−| w | ≤ | z + w |.

    9.| z1 + z2 + … + zn | ≤ | z1 | + | z2 | + … + | zn |, generalized triangle inequality.

    The proofs of properties 1, 2, and 3 follow immediately from the definition of modulus; properties 4 and 5 follow by the use of 3; and properties 7 and 8 are corollaries of the triangle inequality (see Exercise 2.14). Property 9 also follows from the triangle inequality by use of mathematical induction on n. We prove the truth of the triangle inequality in the following example.

    EXAMPLE 3

    Prove the triangle inequality.

    A very brief explanation is given after each step of the proof. The reader will find it instructive to complete the justification when the reason given is less than obvious. We follow a procedure that is usual in proving assertions involving only nonnegative quantities, as is the case with moduli. Specifically, instead of proving the triangle inequality as given above, we prove the squared relation | z + w |² ≤ (| z | + | w |)². Then, since all involved quantities are positive or zero, we can take square roots of both sides to obtain the triangle inequality.

    In the examples that follow, we illustrate the fact that the correspondence between concepts from analytic geometry and complex numbers can be carried one step further to give us what we may call the complex form of equations in the plane.

    EXAMPLE 4

    Show that the equation | z + i | = 2 represents a circle and find its center and radius.

    First, write the given equation in the form

    and note that the left-hand side represents the distance from z to − i. So this equation is satisfied by all points z whose distance from −i is 2. Clearly, the set of all such points is the circle with center at − i [i.e., the point (0, − 1)] and radius 2.

    Alternatively, we obtain the same result by algebraic manipulations. Let z = x + iy. Then the given equation becomes

    from which, by use of the definition of modulus, we obtain

    Finally, by squaring both sides, we have

    which the reader will recognize as the equation of the circle with center at (0, − 1), which is − i, and of radius r = 2.

    EXAMPLE 5

    Find the locus of all points z in the plane that satisfy Im (i ) = 4.

    Letting z = x + iy in the left-hand side of the given equation and simplifying, we obtain

    Hence 1 − y = 4, or y = − 3, which is a horizontal line.

    EXAMPLE 6

    Determine both geometrically and algebraically the locus of all points z such that | z − 2i | = | z + 2 |.

    Geometrically: Reading the given equation from left to right, one can say that it represents all points z in the plane whose distance from 2i is equal to their distance from −2. From plane geometry we know that the locus of all such points is the perpendicular bisector of the line segment joining 2i and −2. By inspection (of a careful drawing that the reader should construct) we find that the locus in question is the line

    Algebraically: Letting z = x + iy in the given equation, we obtain

    Finally, squaring both sides and simplifying, we obtain, as above, the equation of the line

    EXAMPLE 7

    Find the complex form of the equation of the line x + 3y = 2.

    If we let z = x + iy, we know from Exercise 1.17 that

    Then, substituting in the given equation and simplifying, we obtain

    which is a complex equation defining the given line.

    EXAMPLE 8

    Describe by a mathematical relation the totality of all points in the plane that lie inside a circle with center at z0 and of radius r.

    Paraphrasing the problem slightly, we can say that we are seeking all points z whose distance from z0 is less than the radius r. But in terms of complex numbers, the distance between two points in the plane is conveniently given by the modulus of their difference. Therefore, our locus is expressed by the relation

    which describes the interior of the circle with center at z0 and radius r.

    We proceed now to introduce the polar form of a complex number. We begin by recalling that a point in the plane can be expressed either in terms of rectangular coordinates x and y or in terms of polar coordinates r and θ. We also recall that the relations connecting the two coordinate systems are

    and

    Now, given any number

    substitution from equations (1) gives

    which is called the polar form of z. It follows that

    At this point we interrupt the main development to introduce an alternative and very convenient way to express the polar form of a complex number using complex exponentials. To do so, we use the following facts, which are developed later in more detail.

    1.By definition, for any complex number z = a + ib, the complex exponential is defined by

    In particular, if a = 0, then

    2.For any complex numbers z and w, the following properties of the complex exponential hold.

    (a)ez ≠ 0.

    (b)e⁰ = 1.

    (c)ez + w = ezew.

    (f)ez = ez + ²πi.

    (g)If z = a + ib, then | ez | = ea and arg ez = b.

    Certainly, the first four of these properties should be familiar to the reader.

    Returning now to the main development and using the exponential notation, since eiθ = cos θ + i sin θ, we can write the polar form of a complex number z as

    This compact form in which we can write a complex number will greatly facilitate our work in a number of ways. It does not, however, change the fact that, as we discussed earlier, the argument θ of z takes on an infinite number of values, any two of which differ by a multiple of 2π. For example, the number z = −2i can be written in polar form as 2e−πi/² or as 2e³πi/²

    since

    and

    This situation dictates a careful definition of what we mean when we say that two numbers in polar form are equal. We define equality of complex numbers in polar form as follows:

    if and only if

    In other words,

    two complex numbers given in polar form are equal provided that they have the same distance from the origin and their arguments differ by a multiple of 2π.

    EXAMPLE 9

    in polar form.

    We have

    and

    This puts the angle θ in either the second or the fourth quadrant, but the choice is obvious from the position of the given z, and we conclude that

    Therefore,

    where for no particular reason, we have chosen to use the principal value of θ (i.e., Arg z).

    Suppose now that we have two arbitrary complex numbers

    Then, using properties (c) and (d) of the exponentials, given above, we find that

    and

    These two formulas give the polar form of the product and the quotient of two complex numbers. From equation (3), one extracts the following simple rule:

    The product of two complex numbers is a complex number whose modulus is the product of the two moduli and whose argument is the sum of the two arguments.

    A similar rule is obtained from equation (4).

    A convenient formula for the integral powers of any complex number can now be deduced as follows. In equation (3), let w = z = reit. Then repeated use of that equation yields

    and by induction

    for any nonnegative integer n. The extension to negative values of n is immediate by use of equation (4), with z = 1 · e⁰ and w = rnenti.

    With formula (5) at our disposal we are now in a position to find roots (fractional powers) of any complex number c. Of course, this amounts to solving the equation

    for all its roots. So given a nonzero complex number c = ρeiθ, we set out to find all numbers z = reit such that zn = c. Substituting for z and c in the preceding equation, we obtain

    Therefore, according to the definition of equality of two complex numbers in polar form, we must have

    or

    As k takes on n consecutive values (preferably, k = 0, 1, …, n − 1), the last two equations yield one value for r but n distinct values for t, representing n distinct arguments for z; in turn, these values yield the n nth roots of c:

    It can be shown that formula (6) indeed yields the n distinct nth roots of any nonzero c and that any further assignment of values of k yields roots already obtained (see Exercise 2.27). We demonstrate the foregoing process in the following example. It should be emphasized that, in general, the process is identical for any problem of this type.

    EXAMPLE 10

    Find the three cube roots of i.

    In effect, we are solving the equation z³ = i, which, by letting z = reit we can write in polar form as

    Therefore,

    hence

    Letting k = 0, 1, 2, we obtain

    It follows that the three cube roots of i are

    and

    If we plotted these three roots, we would discover that they all lie on the circle with center at the origin and radius r = 1 and are the vertices of an equilateral triangle (i.e., the roots are equally distributed around that circle). It turns out that this symmetric distribution of the roots of a complex number around a circle is a general property that is described in Exercise 2.28.

    As a special case of the development preceding and illustrated by Example 10, one solves the equation

    to find the n nth roots of unity (see Exercise 2.28).

    We close this section with a brief discussion of the geometrical equivalents of the algebraic operations on complex numbers. Conjugation is actually a reflection across the real axis, as Fig. 1.3(a) illustrates. This is easy to see, since conjugation of a complex number simply negates the imaginary part of that number. Addition of complex numbers corresponds to addition of two-dimensional vectors since, by definition, the sum of such numbers is obtained by adding respective components. Consequently, the geometry of the operation of addition is the familiar parallelogram rule used in the addition of vectors in the plane [see Fig. 1.3(b)]. The situation with respect to subtraction is similar [see Fig. 1.3(c)].

    Figure 1.3 Geometry of operations: (a) conjugation; (b) addition; (c) subtraction; (d) multiplication

    The geometry of the product of two complex numbers is based on the rule we derived from equation (3). Thus, given z and w [see Fig. 1.3(d)], form the triangle Δ(0, 1, z). Then with vector w as one of its sides, form the triangle Δ(0, w, P) similar to the first triangle, while keeping the orientation of the equal angles a the same. By similarity, we have

    On the other hand, by construction,

    Thus P is the complex number whose absolute value is the product of the absolute values of z and w and whose argument is the sum of the arguments of those two numbers. Therefore, P is the product of z and w, that is,

    and the product of two complex numbers has been constructed geometrically. An analogous construction yields the geometric equivalent of the quotient of two complex numbers (see Exercise 2.24).

    EXERCISE 2

    A

    2.1Plot the numbers 3 + 4i, 1 − i, − 1 + i, 2, − 3i, e + πi

    2.2Determine whether or not the points − i, 2 + i and − 3 + 2i form a right triangle.

    2.3Prove that | z² | = | z |² is true for all z.

    2.4Write each of the following numbers in polar form.

    (a)−1.

    (b)3.

    (c)−4i

    (d)−2 + 2i.

    (e)

    (f)

    (g)1 − i.

    (h)2 − i.

    (i)

    (j)2 − i.

    2.5Check your work in Exercise 2.4 by transforming your answers back to rectangular form.

    2.6Use the answers to Exercise 2.4 to perform the following operations in polar form.

    (a)(− 2 + 2i)(l − i).

    (b)−4i(−2 + 2i).

    (c)(1 − i)⁶.

    (d)(−2 + 2i)¹⁵.

    2.7In each of the following cases, find the locus of points in the plane satisfying the relation.

    (a)| z − 5 | = 6.

    (b)| z + 2i | ≥ 1.

    (c)Re (z + 2) = − 1,

    (d)Re (i ) = 3.

    (e)| z + i | = | z i |.

    (f)| z + 3 | + | z + l | = 4.

    (g)| z + 3 | − | z + l | = ± l.

    (h)−l ≤ Re(z) < l.

    (i)Im (z) < 0.

    (j)0 < Im (z + 1) ≤ 2π.

    2.8If c is a positive real number and z0 is an arbitrary fixed point in the plane, argue that | z z01 = c describes a circle with center at z0 and radius c.

    2.9Find the six sixth roots of unity and plot them [see Exercise 2.28(b)].

    2.10Find all the roots of the equation z³ + 8 = 0.

    2.11Solve the equation z² + i = 0 and use your answer to solve z⁴ + 2iz² − 1 = 0.

    HINT:Square both sides of the first equation.

    2.12Find the three cube roots of unity. Then prove that the second and third powers of at least one of them yield the other two roots [see Exercise 2.28(a)].

    2.13Use the geometric property of the roots of unity described in Exercise 2.28(b) to write the polar form of the 12 roots of z¹² − 1 = 0 without solving the equation. Plot the roots.

    B

    2.14Review the paragraph preceding Example 3 and prove the following identities.

    (a)| z | = | −z |.

    (b)| z w | = | w z |.

    (c)| z .

    (d)| zw | = | z | · | w |.

    (e)

    (f)| | z | − | w | | ≤ |z w |

    (g)| Re(z) | ≤ | z |.

    (h)| Im (z) | ≤ | z |.

    (i)| z | − | w | ≤ | z + w |.

    2.15Choose an arbitrary complex number z and plot the points

    2.16Prove that any point of the form z = eit for t = real lies on the circle x² + y² = 1.

    2.17Use mathematical induction to derive formula (5).

    2.18Prove that for any z, arg z = 2kπ, where k = integer.

    2.19Prove that for any z ≠ 0 and w ≠ 0,

    C

    2.20Under what conditions would equality hold in each of the relations of Exercise 2.14(g) and (h)?

    2.21Prove that the equation z² + 2z + 5 = 0 cannot be satisfied by any z such that | z | ≤ 1.

    HINT:Prove by contradiction. Assume that a ζ exists such that | ζ | ≤ 1 and ζ² + 2ζ + 5 = 0. Therefore, − 5 = ζ² + 2ζ. Now use the triangle inequality to arrive at a contradiction.

    2.22If | z | = 1, prove that | z w z | for any w.

    2.23Prove that if z + 1/z is real, then either Im (z) = 0 or | z | = 1.

    2.24Construct geometrically the quotient of two complex numbers using a method similar to that used at the end of this section to construct the product of two numbers.

    2.25If m and n are integers that have no common factors except 1 or − 1 and if z = reit prove that for k = 1, 2, …, n − 1,

    2.26Denoting by w any one of the complex nth roots of unity, prove that

    2.27Prove the statement immediately following formula (6).

    2.28Prove the following two properties satisfied by the n nth roots of unity.

    (a)Algebraic property: If the n roots are given by formula (6), then consecutive powers of z1 yield z2, z3, …, zn − 1 and z0.

    (b)Geometric property: The n nth roots of unity are the vertices of a regular polygon of n sides inscribed in the circle | z | = 1 and one of whose vertices is z = 1. Put differently: The roots of unity are evenly distributed around the circle | z | = 1 starting at z = 1.

    REVIEW EXERCISES—CHAPTER 1

    1.Perform the following operations.

    (a)

    (b)

    (c)(−4)¹/⁴.

    (d)(1 + i)¹⁸⁰.

    (e)1¹/⁸.

    (f)

    (g)

    (h)

    (i)(−1 + i)¹/³.

    (j)

    2.Mark the following statements true or false. If true, prove; if false, give a counterexample.

    (a)If c is a real number, then c .

    (b)If z is pure imaginary, then z .

    (c)i < 2i.

    (d)The argument of z = 0 is zero.

    (e)There is at least one number z such that − z = z−1.

    (f)If z ≠ 0, then arg z has an infinite number of distinct values.

    (g)+ i) = 0 is a circle.

    (h)For any real t, | cos t + i sin t | = 1.

    (i)The relation | z w| ≥ | z | − | w | is always true.

    (j)The relation reit = ρeiθ implies that r = ρ and t = θ.

    3.Under what conditions is | z + w | = | z | + | w |?

    4.Identify all the points in the plane that satisfy | z − 2 | ≤ | z |.

    5.Describe and sketch the following loci.

    (a) .

    (b)0 < arg z < π.

    (c)π < arg z < 8π.

    6.Prove that if | z | < 1, then Re (z + 1) > 0.

    7.Show that the equation z z 0 − z= r² − a² − b² represents a circle of radius r and center z0 = a + ib.

    8.If each of the points z, w, and v has an absolute value of 1 and if z + w + v = 0, prove that they are equidistant from each other.

    9.If z, w, and v are three distinct points on a circle centered at the origin, show that

    10.If z, w, and v lie on the same line, prove that

    Prove that the converse is also true.

    11.Prove that with the exception of zero, the relation z holds only for pure imaginaries.

    12.Prove the following relations.

    (a)Re (z + w) = Re (z) + Re (w).

    (b)Im (z + w) = Im (z) + Im (w).

    (c)Re (zw) = Re (z)Re (w) − Im (z)Im (w).

    (d)Im (zw) = Re (z)Im (w) + Im (z)Re (w).

    13.for all its roots.

    14.If z = eit, prove the following relations.

    (a)zn + l/zn = 2 cos nt.

    (b)zn − l/zn = 1/zn sin nt.

    15.Prove: If Im (z + w) = 0 = Im (zw), then z or z and w are real.

    16.Consider the totality of all numbers of the form

    Prove that any complex number z can be uniquely written as z = , where r is some nonnegative real number.

    17., for any complex number z.

    18.If the coefficients a0, al, …, an of the polynomial

    .

    19.In Appendix 1(A) we prove that the set C of complex numbers forms a mathematical structure called a field. In general, a field F is called an ordered field, provided that it contains a positive subset P with respect to which the following axioms hold.

    (a)If x is in F, then one and only one of the following is true:

    (b)If x and y are elements in P, then so is their product xy.

    (c)If x and y are elements of P, then so is their sum x + y.

    Prove that C is not an ordered field.

    APPENDIX 1

    Part A: A Formal Look at Complex Numbers

    An ordered pair of real numbers is denoted (a, b). In saying that the pair is ordered we mean that (a, b) and (b, a) are distinct entities unless a = b.

    The complex number system C is defined to be the totality of all ordered pairs (x, y) of real numbers, where equality, addition, and multiplication are defined, respectively, as follows:

    Any ordered pair of real numbers will henceforth be called a complex number.

    Under the operations defined by (2) and (3), C forms an algebraic system called a field; more specifically, C satisfies the following 11 laws: For any complex numbers z = (a, b) w = (c, d) and v = (e, f) we have:

    Closure Laws:

    A.1. z + w is a complex number.

    M.1. zw is a complex number.

    Commutative Laws:

    A.2. z + w = w + z.

    M.2. zw = wz.

    Associative Laws:

    A.3. z + (w + v) = (z + w) + v.

    M.3. z(wv) = (zw)v.

    Identities:

    A.4. There is a number α in C such that z + α = z.

    M.4. There is a number β in C such that zβ = z.

    Inverses:

    A.5. For each z in C there is a z′ such that z + z′ = α; see A.4.

    M.5. For each z ≠ α in C there is a z″ such that zz″ = β; see M.4.

    Distributive Law:

    D. z(w + v) = zw + zv.

    The number α of A.4 is called the zero of the system, and it is unique (see Exercise 1.25). The number z′ of A.5 is called the negative of z, and it, too, is unique for each z. The number β of M.4 is called the unity of the system, and z″ of M.5 is called the reciprocal of z; here, too, β is unique and so is z″ for a given z ≠ α.

    We proceed to prove some of the foregoing properties of C; the reader should provide proofs for the remaining ones.

    A.1 and M.1 are clearly true since the right-hand sides of (2) and (3) are ordered pairs of real numbers and are, therefore, complex numbers.

    A.2 is proved as follows:

    Note that in the process, we have used the commutative property of the real numbers. M.2 is proved analogously. A.3 is proved as follows:

    Here again, we have used the associativity of the reals. M.3 is proved by a similar process.

    A.4 is an existence claim. To prove its truth, we must produce a specific complex number α with the prescribed property. We begin by assuming that such a number exists, say, α = (x, y). Then for any complex number z = (a, b) we must have z + α = z; that is, (a, b) + (x, y) = (a, b). But then (a + x, b + y) = (a, b) and by equation (1), a + x = a and b + y = b. Therefore, x = 0 and y = 0, and hence if a is to exist, it must be of the form

    Clearly, α has the desired property, as one can easily verify.

    M.4 is established in a similar fashion. Thus we begin by assuming that β = (x, y) and has the desired property; that is, for any z = (a, b) ≠ (0, 0),

    Then

    hence

    This is a system of two equations in two unknowns, x and y, which upon solving we find that x = 1 and y = 0. Therefore,

    EXERCISE : Why is the number z = (0, 0) excluded from this property?

    We leave the proofs of the remaining properties as an exercise for the reader.

    The reader who is familiar with the concept of a vector space will recognize the complex number system C as a two-dimensional vector space over the field of real numbers. In this context a complex number (x, y) can be thought of as a vector with vector addition defined by (2). If one defines scalar multiplication by

    for any real number r and any complex number (x, y) it is an easy exercise to show that the postulates of a vector space are satisfied. Moreover, a basis for this vector space is given by the vectors

    This, of course, implies that any vector (x, y) in C can be written as a linear combination of the basis vectors; indeed, using (4), we find that

    Clearly, v1 is the unity of C. One would then expect that, perhaps, v2 is also a special type of a vector when viewed as a complex number. It turns out that this is indeed the case. For we find that

    that is, the square of v2, taken as a complex number, is − v1. We conclude then that v2 corresponds to the imaginary unit i of the complex number system. Relation (6) plays a fundamental role in the translation we are about to effect on the complex numbers.

    The traditional form of complex numbers as developed in this chapter is obtained from the foregoing development through the following identifications:

    with the relation in (6) corresponding to i² = − 1. Then, by use of (5), we have the identification

    which, as we indicated at the beginning of Section 2, allows one to say that a complex number is a two-dimensional vector.

    EXERCISE A1(A)

    1.Prove that the identification (x, y) ↔ x + yi preserves the operations on complex numbers as defined, on the one hand, by (2) and (3) in this appendix and, on the other, by the relations defining the same operations in Section 1.

    Part B : Stereographic Projection

    An alternative and, in some respects, very interesting way of looking at complex numbers is by means of the concept of stereographic projection, which we describe in what follows.

    Consider the z-plane and take a sphere of diameter 1, tangent to the plane at its origin (see Fig. 1.4). In terms of three-dimensional rectangular coordinates, the point of tangency is (0, 0, 0). Then the center C of ). We shall call the point of tangency the south pole, and the point N(0, 0, 1) the north pole of . The entire configuration is often referred to as the Riemann sphere.

    It is evident that a line joining any point z = x + iy of the z-plane to the north pole will pierce the sphere at a unique point Ρ(α, β, γ). Similarly, for any such point P on the sphere, the line joining P with the north pole will, when extended, yield a unique point z in the plane—with one notable exception: the north pole itself. The coordinates α, β, and γ of P are related to those of z by the formulas

    The inverse relations are given by

    Clearly, this process, which is called stereographic projection, creates a one-to-one correspondence between the points in the plane and those of the sphere (except N). The fact that the north pole corresponds to no point in the plane should be obvious to the reader, at least intuitively. Algebraically, this fact is obvious from equations (2), since N is the only point (α, β, γ) on the sphere for which γ = 1.

    A closer inspection of equations (2) will show that points in the immediate vicinity of the north pole correspond to points in remote areas of the

    Figure 1.4 Riemann sphere

    z-plane; for, if a point is very near N, then its third coordinate γ is very near 1 and, in that case, we obtain a point z of very large modulus. Conversely, if we take a point z of very large modulus, then equations (1) place a and β very close to 0, whereas γ is very near (but remains less than) 1. So, as we take points z with larger and larger moduli, we approach the point N(0, 0, 1) of the sphere.

    The preceding discussion suggests that the exception in the correspondence between the points on the sphere and those of the plane can be eliminated if we adjoin to the z-plane an ideal point with modulus larger than the modulus of any point in the plane and make that point correspond to the north pole; this we proceed to do. We thus adjoin to the z-plane the point at infinity, denoted ∞, having the property that

    for every complex number z. The complex plane augmented with this ideal point is called the extended complex plane. We can then say that the stereo-graphic projection creates a one-to-one correspondence between the Riemann sphere and the extended complex plane, without exception.

    Going further with the correspondence created by the stereographic projection, the reader will find it interesting to prove that the following are true:

    1.The unit circle | z | = 1 corresponds to the equator of , while the circle’s interior maps onto the entire southern hemisphere, and its exterior onto the northern hemisphere.

    2.A line in the plane that passes through the origin, that is, a line of the form y = kx, corresponds to a circle on the sphere that passes through both the north and the south poles, assuming that the ideal point at infinity, as a point of the plane, is used.

    3.A line y = mx + b, with b ≠ 0, in the extended complex plane corresponds to a circle on passing through the north pole.

    4.A spherical cap about the north pole maps onto an outer ring of the plane consisting of all points z such that | z | > M for some real number M.

    5.Any circle or straight line in the plane corresponds to a circle on the sphere.²

    We close this appendix with a brief discussion of the concept of distance between two points of the Riemann sphere as it relates to the distance

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