Statistical Independence in Probability, Analysis and Number Theory
By Mark Kac
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About this ebook
The treatment begins with an examination of a formula of Vieta that extends to the notion of statistical independence. Subsequent chapters explore laws of large numbers and Émile Borel's concept of normal numbers; the normal law, as expressed by Abraham de Moivre and Andrey Markov's method; and number theoretic functions as well as the normal law in number theory. The final chapter ranges in scope from kinetic theory to continued fractions. All five chapters are enhanced by problems.
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Statistical Independence in Probability, Analysis and Number Theory - Mark Kac
THEORY
CHAPTER 1
FROM VIETA TO THE NOTION OF STATISTICAL INDEPENDENCE
1. A formula of Vieta. We start from simple trigonometry. Write
From elementary calculus we know that, for x ≠ 0,
and hence
Combining (1.2) with (1.1), we get
A special case of (1.3) is of particular interest. Setting x = π/2, we obtain
a classical formula due to Vieta.
2. Another look at Vieta's formula. So far everything has been straightforward and familiar.
Now let us take a look at (1.3) from a different point of view.
It is known that every real number t, 0 ≤ t ≤ 1, can be written uniquely in the form
where each є is either 0 or 1.
This is the familiar binary expansion of t, and to ensure uniqueness we agree to write terminating expansions in the form in which all digits from a certain point on are 0. Thus, for example, we write
rather than
The digits єi are, of course, functions of t, and it is more appropriate to write (2.1) in the form
With the convention about terminating expansions, the graphs of є1(t), є2(t), є3(t), · · · are as follows:
It is more convenient to introduce the functions ri(t) defined by the equations
whose graphs look as follows:
These functions, first introduced and studied by H. Rademacher, are known as Rademacher functions. In terms of the functions rk(t), we can rewrite (2.2) in the form
Now notice that
and
Formula (1.3) now assumes the form
and, in particular, we have
An integral of a product is a product of integrals!
3. An accident or a beginning of something deeper? Can we dismiss (2.5) as an accident? Certainly not until we have investigated the matter more closely.
Let us take a look at the function
It is a step function which is constant over the intervals
and the values which it assumes are of the form
Every sequence (of length n) of + l's and – 1's corresponds to one and only one interval (s/2n, (s + 1)/2n). Thus
where the outside summation is over all possible sequences (of length n) of + 1's and – 1's.
Now
and consequently
Setting
we obtain
and, since
uniformly in (0, 1), we have
We have thus obtained a different proof of formula (1.3). Is it a better proof than the one given in § 1?
It is more complicated, but it is also more instructive because it somehow connects Vieta's formula with binary digits.
What is the property of binary digits that makes the proof tick?
4. (n times). Consider the set of t's for which
One look at the graphs of r1, r2, and r3 will tell us this set (except possibly for end points) is simply the interval